Show how to find the deltaHf° for 1 mol of cyclohexane starting from graphite and H2(g). Cite where you get any values you use in all calculations.
Cyclo hexane is C6H12
6C (g) + 6H2 ---->C6H12
since you have not given this data. We need to get the data using other mechanisms.
C6H12 + 9 O2 --->6 CO2 + 6 H2O ΔH° = -3920 kJ
C + O2 -----> CO2 ΔH° = -394 kJ
H2 + 1/2 O2 ----> H2O ΔH° = -286 kJ
data source:
https://en.wikipedia.org/wiki/Standard_enthalpy_change_of_formation_%28data_table%29
we will use above 3 equations to get our equation.
6*eqn 2 + 6*eqn 3 - eqn 1 will give us our equation.
delta Hf of cyclohexane= 6*(-395) + 6*(-286) - (-3920) = 166
KJ/mol
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