Sample | Extinction Coefficient L / (mole*cm) | A260 | A280 | A320 | A260/A280 | OD260 | MW |
---|---|---|---|---|---|---|---|
Uknown 1 |
196800 | .33 | .21 | .1 | 1.57 | 29 | 6167 |
Unknown 2 | 191800 | .32 | .21 | .11 | 1.52 | 29 | 6311 |
Unknown 3 | 190200 | .34 | .21 | .1 | 1.62 | 28 | 6127 |
Dilution factor of 1:30
(5 part sample / 150 part solution)
Given this set of data, how to calculate concentration of the unknowns?
Solution:
By beer-lamberts law, A = Elc {E ------> extinction co-efficient}
c = A / El
Sample | Extinction Coefficient L / (mole*cm) | A260 | A280 | A320 | A260/A280 |
unknown 1 | 196800 | 0.33 | 0.21 | 0.1 | 1.57 |
unknown 2 | 191800 | 0.32 | 0.21 | 0.11 | 1.52 |
unknown 3 | 190200 | 0.34 | 0.21 | 0.1 | 1.62 |
unknown 1 | c = A / El | 1.67683E-06 | 1.06707E-06 | 5.0813E-07 | 7.9776E-06 |
unknown 2 | 1.6684E-06 | 1.09489E-06 | 5.73514E-07 | 7.9249E-06 | |
unknown 3 | 1.78759E-06 | 1.1041E-06 | 5.25762E-07 | 8.5174E-06 | |
dilution | 1/30 = 1:30 | 5.03049E-05 | 3.20122E-05 | 1.52439E-05 | 0.00023933 |
5.00521E-05 | 3.28467E-05 | 1.72054E-05 | 0.00023775 | ||
5.36278E-05 | 3.3123E-05 | 1.57729E-05 | 0.00025552 |
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