Sodium fluoride has a solubility of 3.84 g in 100.0 g of water at 18°C. Express this solute concentration in the following terms:
mass of solute = 3.84 g
moles of solute = 3.84 / 58.5
= 0.0656
mass of solvent = 100 g = 0.1 kg
molality = moles of solute / mass of solvent
= 0.0656 / 0.1
= 0.656 m
molality = 0.656 m
Get Answers For Free
Most questions answered within 1 hours.