Considering the ideal behaviour of the gas sample (as anything is not mentioned here) , we know that for ideal gas
P1V1 = P2V2 (at constant temperature) ; where P1 & V1 is the initial pressure and volume of the gas
P2 & V2 is the final pressure and volume of the gas respectively .
In the given question , P1 =0.75 atm , V1 =2.0 L and P2 = 1.75 atm ,V2 =?
therefore , V2 = P1V1 / P2 = (0.75*2.0)/(1.75) L =0.86 L
So , volume of the gas is 0.86 L when pressured of the gas is increased to 1.75 atm at constant temperature .
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