Question

How many grams of Ca(NO2)2 must be added to 4.0 L solution of 0.1 M HNO2...

How many grams of Ca(NO2)2 must be added to 4.0 L solution of 0.1 M HNO2 to get a pH of 3.64?

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Homework Answers

Answer #1

Solution:

The balanced chemical rection is,

2 HNO2 + Ca(OH)2 = Ca(NO2)2 + 2 H2O

Molar mass of Ca(OH)2 = 74.093 g/mol

Molar mass of Ca(NO2)2 = 132.089 g/mol

Molar mass of HNO2 = 47.013 g/mol

molar mass of water = 18 g/mol

[HNO2] = 0.1 M               pH = 3.64 --> [H+] = 10-3.64 = 0.000229 M

Molarity = Moles / Volume in Litre

0.000229 = (Ca(NO2)2 in grams / 132.089) / 4.0 L

Ca(NO2)2 in grams = 0.12 grams

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