Question

Trial	Volume of H2SO4, (mL)	Vinitial NaOH, (mL)	Vfinal NaOH, (mL)	Molarity H2SO4, (mol/L)	Molarity of NaOH, (mol/L)
1	14.60	50.00	38.90	0.1468	0.2019
2	14.90	38.90	24.60	0.1649	0.2132
3	15.15	24.60	13.20	0.1684	0.2122

a.) Calculate the number of moles of OH^- for each trial for the titration of H2SO4 with NaOH. Determine the average number of moles of OH^-

b.) From your calculation in part a, calculate the molarity of H⁺ ions in your sample of H2SO4

Answer 1

Moles of OH- = molarity * volume in L

For Trial 1 :

moles of OH- = 0.2018 M * 0.0111 L = 2.24*10^-3 moles

For trial 2 :

moles of OH- = 0.2132 M * 0.0143 L = 3.05*10^-3 moles

For trial 3 :

moles of OH- = 0.2122 M * 0.0114 L = 2.42*10^-3 moles

average number of moles = 7.71*10^-3 moles

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moles of H+ ion = moles of OH- ion

average volume of H2SO4 = 14.88 mL = 0.01488 L

Molarity of H+ ion = 7.71*10^-3 moles/0.01488 L = 0.518 M