How many oxygen atoms are in 22.1g Al2O3
1 mole Al2O3 = 3 mol O-atoms
so that, no of mole of Al2O3 = w/mwt = 22.1/102 = 0.217 mol
no of O-atoms = 0.217*3*6.023*10^23 ( 1mol = 6.023*10^23 atoms)
= 3.921*10^23 atoms
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