Question

the overall formation constant for Ag(CN)2- equals 5.3 x 10 18, and the Ksp for AgCN...

the overall formation constant for Ag(CN)2- equals 5.3 x 10 18, and the Ksp for AgCN equals 6.0 x 10-17. Calculate Kc for AgCN(s) +CN- makes Ag(CN)2

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Ag^+ (aq) + 2CN^- (aq) -------------> [Ag(CN)2]^-      Kf = 5.3*10^18

Kf   = [Ag(CN)2]^- /[Ag^+][CN^-]^2

AgCN(s) --------------> Ag^+(aq) + CN^- (aq)               Ksp = 6*10^-17

Ksp   = [Ag^+][CN^-]

Kf *Ksp   = [Ag(CN)2]^- /[Ag^+][CN^-]^2 * [Ag^+][CN^-]

                 = [Ag(CN)2]^- /[CN^-]

Kf*Ksp     = kc

5.3*10^18 *6*10^-17   = kc

kc   = 318>>>>>answer

Kc for AgCN(s) +CN- -------> Ag(CN)2 is 318 >>>>>answer

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the formation constant Kf for Ag(cn)2- if the cell develop a potential of -0.425v. Ag(cn)2-=7.50*10^-3...
Calculate the formation constant Kf for Ag(cn)2- if the cell develop a potential of -0.425v. Ag(cn)2-=7.50*10^-3 M and CN- =0.0175 M.PLEASE SHOW STEP BY STEP .IT IS A 10 MARKS QUESTION
(A) Using the Ksp for Cu(OH)2 (1.6 x 10^-19) and the overall formation constant for Cu(NH3)4...
(A) Using the Ksp for Cu(OH)2 (1.6 x 10^-19) and the overall formation constant for Cu(NH3)4 (1.0 x 10^13), calculate a value for the equilibrium constant for the reaction: Cu(OH)2(s) + 4NH3(aq) <===> Cu(NH3)4(aq) + 2OH-(aq) (B) Use the value of the equilibrium constant you calculated in Part A to calculate the (approximate) solubility (in mols/liter, M) of Cu(OH)2 in 5.0 M NH3. In 5.0 M NH3 the concentration of OH- is 9.5 x 10^-3 M. (Although not strictly correct...
Calculate the equilibrium constant Kc for the net reaction show below AgI(s) + 2NH3(aq) <> Ag(NH3)2+(aq)...
Calculate the equilibrium constant Kc for the net reaction show below AgI(s) + 2NH3(aq) <> Ag(NH3)2+(aq) + I-(aq) For AgI, Ksp=8.3*10^-17 For Ag(NH3)2+ , Kf=1.5*10^7
The formation constant for the [CuEDTA]^2- complex is 6.3 x 10^18 at T = 25 degrees...
The formation constant for the [CuEDTA]^2- complex is 6.3 x 10^18 at T = 25 degrees C. Cu^2+ (aq) + EDTA^4- (aq) = [CuEDTA]^2- (aq) Given that Ksp for Cu(OH)_2 (s) = 4.8 x 10^-20 what is the equilibrium constant for the following reaction? Cu(OH)_2(s) + EDTA^4- (aq) = [CuEDTA]^2- (aq) + 2OH^- (aq) A) 8.3 x 10^4 B) 1.0 x 10^21 C) 1.7 x 10^5 D) 0.30 E) 1.2 x 10^37 F) 3.3 x 10^38 G) 3.3
The solubility product constant for Zn(OH)2 is Ksp=3.00*10^-16 The formation constant for the hydroxo complex Zn(OH)4^2-...
The solubility product constant for Zn(OH)2 is Ksp=3.00*10^-16 The formation constant for the hydroxo complex Zn(OH)4^2- is Kf=4.60*10^17 When Zn(OH)2(s) was added to 1.00 L of a basic solution, 1.19
Calculate the value of the equilibrium constant, Kc, for the following reaction. FeS(s) + 6CN-(aq) <----->...
Calculate the value of the equilibrium constant, Kc, for the following reaction. FeS(s) + 6CN-(aq) <-----> [Fe(CN)6]4-(aq) + S2-(aq) Kc=______? The solubility product constant, Ksp, for FeS is 1.6 × 10^–19, and the formation constant, Kf, for [Fe(CN)6]^4– is 1.5 × 10^35 Kc=______
Calculate Kc of the following reaction: CuBr(s)+Br-(aq)----> CuBr2-(aq) The solubility product constant, Ksp, for CuBr is...
Calculate Kc of the following reaction: CuBr(s)+Br-(aq)----> CuBr2-(aq) The solubility product constant, Ksp, for CuBr is 6.27× 10–9 and the overall formation constant, Kf (β2), for CuBr2– is 8.0× 105.
Calculate the value of the equilibrium constant for the reaction below. Ksp for Ag2S is 6.0...
Calculate the value of the equilibrium constant for the reaction below. Ksp for Ag2S is 6.0 × 10−51...... Kf for Ag(NH3)2+ is 1.7 × 107. Ag2S(s) + 4 NH3(aq) ↔ 2 Ag(NH3)2+(aq) + S2−(aq)
Mn^+2 (ag) + C2O4^-2 (ag) <----> MnC2O4 (aq) K1= 7.9 x 10^3 MnC2O4(aq) + C2O4 (aq)...
Mn^+2 (ag) + C2O4^-2 (ag) <----> MnC2O4 (aq) K1= 7.9 x 10^3 MnC2O4(aq) + C2O4 (aq) <------> Mn(C2O4)2 ^-2 K2= 7.9 x 10^1 Calculate the value for the overall formation constant for Mn(C2O4)2^-2 K= [Mn(C2O4)2^-2]          ------------------       [Mn^2+] [C2O4^-2]^2 Please be very detailed and do not skip over any of the math. Thank you!
1. AgCl (s) <-> Ag+ (aq) + Cl- (aq) Ksp = 1.8 x 10^-10 Ag+ (aq)...
1. AgCl (s) <-> Ag+ (aq) + Cl- (aq) Ksp = 1.8 x 10^-10 Ag+ (aq) + 2S2O3^2- (aq) <-> Ag(S2O3)2^3- Kf = 2.9 x 10^13 Consider the two above equilibria. If sodium thiosulfate solution were added to a solution containing the silver chloride equilirbium (first equilibrium above) the silver chloride equilibrium would shift toward the reactants (TRUE OR FALSE) 2. AgCl (s) <-> Ag+ (aq) + Cl- (aq) Ksp = 1.8 x 10^-10 Ag+ (aq) + 2S2O3^2- (aq) <->...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT