Question

The crystalline hydrate Cd(NO3)2 ⋅ 4H2O(s) loses water when placed in a large, closed, dry vessel at room temperature: Cd(NO3)2⋅4H2O(s)→ Cd(NO3)2(s) +4 H2O(g) This process is spontaneous and ΔH∘ is positive at room temperature.

A) What is the sign of ΔS∘ at room temperature? Positive or Negative?

B) If the hydrated compound is placed in a large, closed vessel that already contains a large amount of water vapor, does ΔS∘ change for this reaction at room temperature? Can someone please help me with this problem, thank you!

Answer 1