Question

What volume of gas can be produced from the decomposition of 4.34 g of ferrous carbonate at 792 torr and 20* C?

Answer 1

we know that

moles = mass / molar mass

so

moles of FeC03 = 4.34 / 115.8539

moles of FeC03 = 0.037461

now

consider the decomposition of FeC03

the balanced equation is

FeC03 ---> FeO (s) + C02

we can see that

moles of C02 produced = moles of FeC03 decomposed = 0.037461

now

for gases

PV = nRT

given

P = 792 / 760 atm

R = 0.0821

T = 20 + 273 = 293 K

so

using those values

we get

( 792 / 760) x V = 0.037461 x 0.0821 x 293

V = 0.8647 L

V = 864.7 ml

so

864.7 ml of C02 gas can be produced