Question

Sixty grams of CuSO4 are dissolved and diluted to 800 mL. This solution is diluted 1/5 and then rediluted 3/100. How many grams of CuSO4 would be present in 1 liter of the final solution? Report to the nearest 1/100. Sixty grams of CuSO4 are dissolved and diluted to 800 mL. This solution is diluted 1/5 and then rediluted 3/100. How many grams of CuSO4 would be present in 1 liter of the final solution? Report to the nearest 1/100.

Answer 1

molar mass of CuSO4 = 159.6 g/mol
number of mole of CuSO4 = (given mass)/(molar mass)
= 60/159.6
= 0.376 mole

volume = 800 mL
= 0.8 L
molarity = (number of mole)/(volume in L)
= 0.376/0.8
= 0.47 M

it diluted 1/5times
molarity = 0.47/5
= 0.094 M
again diluted by 3/100
molarity = (3/100)*0.094
= (2.82*10^-3) M

number of mole of CuSO4 in 1 L of this solution = (2.82*10^-3)
mass of CuSO4 = (number of mole)*(molar mass)
= 2.82*10^-3*159.6
= 0.45 g

Answer : 0.45 g