Question

Sixty grams of CuSO4 are dissolved and diluted to 800 mL. This solution is diluted 1/5 and then rediluted 3/100. How many grams of CuSO4 would be present in 1 liter of the final solution? Report to the nearest 1/100. Sixty grams of CuSO4 are dissolved and diluted to 800 mL. This solution is diluted 1/5 and then rediluted 3/100. How many grams of CuSO4 would be present in 1 liter of the final solution? Report to the nearest 1/100.

Answer #1

molar mass of CuSO4 = 159.6 g/mol

number of mole of CuSO4 = (given mass)/(molar mass)

= 60/159.6

= 0.376 mole

volume = 800 mL

= 0.8 L

molarity = (number of mole)/(volume in L)

= 0.376/0.8

= 0.47 M

it diluted 1/5times

molarity = 0.47/5

= 0.094 M

again diluted by 3/100

molarity = (3/100)*0.094

= (2.82*10^-3) M

number of mole of CuSO4 in 1 L of this solution =
(2.82*10^-3)

mass of CuSO4 = (number of mole)*(molar mass)

= 2.82*10^-3*159.6

= 0.45 g

Answer : 0.45 g

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