Question

calculate the molarity of a .60% percent of NaOCI solution and .30% of a [OCI]- solution. Assume 100g of each solution

Answer 1

For 60% NaOCl solution

mass of NaOCl = 100 g x 60/100 = 60 g

mass of solvent = 40 g = 40 ml

with density of water = 1 g/ml, mass = volume

concentration of [NaOCl] = 60 g/74.44 g/mol x 0.04 L = 20.15 M

If instead it is a 0.60% solution,

Molarity = 0.6 g/74.44 g/mol x 0.0994 = 0.08 M

For 30% NaOCl solution

mass of NaOCl = 100 g x 30/100 = 30 g

mass of solvent = 70 g = 70 ml

with density of water = 1 g/ml, mass = volume

concentration of [NaOCl] = 30 g/74.44 g/mol x 0.07 L = 5.76 M

If instead it is a 0.30% solution,

Molarity = 0.3 g/74.44 g/mol x 0.0997 = 0.04 M