Question

k=0.25 for the reaction: 2NOBr (g) <--> 2NO (g) + Br (g). At the same T and P, what is the K for NO (g) + 1/2Br2 (g) <--> NOBr (g)?

Answer 1

Solution-

Given-

2NOBr (g) <--> 2NO (g) + Br (g)   K= 0.25 …………………………… 1

Let’s balance reaction

2NOBr (g) <--> 2NO (g) + Br2 (g)   K= 0.25 …………………………. 2

The given reaction is reversible, let’s write the reaction reverse manner

2NO (g) + Br2 (g) <--> 2NOBr (g) …………………………. 3

Dissociation constant (K) becomes inversed then K becomes

K = 1/0.25 = 4

Now divide reaction 3 by 2 then reaction & K becomes

NO (g) + 1/2 Br2 (g) <--> NOBr (g)

K = 4/2

K = 2

Answer K = 2 for reaction NO (g) + 1/2Br2 (g) <--> NOBr (g)