Earth’s population is about 6.5 billion. Suppose that
every person on Earth participates in a process of
counting identical particles at the rate of two particles per
second. How many years would it take to count
6.0 3 1023 particles? Assume that there are 365 days
in a year.
Total population of Earth = 6.5 billion = 6.5x109 people
Given each people counts 2 particles per second.
Total seconds in 1 year = 1 year x (365 day/1 year) x (24 hr / 1 day) x (60 min / 1 hr) x (60 s / 1 min)
= 365x24x60x60 s = 31536000 s
Hence number of particles counted by 1 person per year = 31536000 s x 2 particles / s
= 63072000 particles / people = 6.3072x107 particles / people
Hence total number of particles counted by 6.5 billion people per year
= (6.3072x107 particles / people) x 6.5x109 people = 4.10x1017 particles / population /year
Hence number of years required to count 6.03x1023 particles
= (1 / 4.10x1017 particles/year) x 6.03x1023 particles = 1.471 x 106 years or 1.471 million years (answer)
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