How many moles of carbon will react with 15.8mol of iron(III) oxide according to the following reaction?
2Fe2O3 + 3C → 4Fe + 3CO2
What mass of sodium nitride is required to produce 12.8g of nitrogen?
2Na3N → N2 + 6Na
If 21.5g of nitrogen is produced in the following reaction, what mass of sodium is also produced?
2Na3N → N2 + 6Na
2Fe2O3 + 3C ----------> 4Fe + 3Co2
2 moles of Fe2O3 react with 3 moles of C
15.8 moles of Fe2O3 react with = 3*15.8/2 = 23.7 moles of C
Q2
2Na3N -----------> N2 + 6Na
1 moles of N2 produced from 2 moles of Na3N
28g of N2 produced from 2*83g of Na3N
12.8g of N2 produced from = 2*83*12/28 = 71.14g of Na3N
Q3
2Na3N -----------> N2 + 6Na
1 moles of N2 produced from 2 moles of Na3N
28g of N2 produced from 2*83g of Na3N
21.5g of N2 produced from = 2*83*21.5/28 = 127.46g of Na3N
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