For each of the following atoms or ions determine # protons, # electrons and #neutrons:
119Sn4+ # of protons___ # electrons____ #neutrons_____
201Hg # of protons____ # electrons ____ #neutrons_____
1. 119Sn4+
Mass no = 119
Mass no is the sum of no.of electrons + no. of neutrons
Now, atomic no of Sn = 50
Since, atomic no. = no. of protons =50
So, no. of neutrons = Mass no. - Atomic no. = 119-50 = 69
No. Of neutrons = 69
No.of electrons = no. of protons in a neutral atom
So, no. of electrons = 50-4(since +4 means lost 4 electrons)
= 46
2. 201Hg
Mass no = 201
Atomic no = 80
So, no of protons = no of electrons = 80
no. of neutrons = Mass no-Atomic no. = 201-80 = 121
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