Part B
What is the final concentration of Dat equilibrium if the initial concentrations are [A] = 1.00 mol L−1 and [B] = 2.00 mol L−1 ?
Express your answer to two significant figures and include the appropriate units.
The reversible chemical reaction
A(aq)+B(aq)⇌C(aq)+D(aq)
has the following equilibrium constant:
K=[C][D][A][B]=2.5
Part A
Initially, only A and B are present, each at 2.00 mol L−1. What is the final concentration of A once equilibrium is reached?
Express your answer to two significant figures and include the appropriate units.
You have
Part A
You have
From the reaction, you can see that at equilibrium C and D have the same concentration (because they have the same stoichiometric coefficient), and the concetration of B and A should be less the initial, and still the same concentration. So at equilibrium:
The K estabilshes the ration at equilibrium of all the species in the reaction. using the equation for K you can calculate X:
This yields an equation as follows:
and can be solve with the quadratic equation:
X=1.225M
so A at equilibrium is 2-1.225=0.775mol/L
Part B
As in part A, the only difference is that A and B are not equal:
Intial
Equilibrium
At equilibirum
This yields an equation as follows:
and can be solve with the quadratic equation:
X=0.792mol/L=D
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