Question

Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, the reaction of 5.0 grams of O2 with 6.0 grams of S can theoretically produce how many grams S O3 in this experiment?

S (s) + O2 (g) → SO3 (g) (not balanced)

Answer 1

first write the balanced equation

2S (s) + 3O2 (g) → 2SO3 (g)

no of moles of O2 = 5.0 g / 32.0g.mol = 0.1562 moles

no of moles S = 6.0 g / 32 g/mol = 0.187 mole

2 moles of S and 3 moles of O2 will give 2 moles of SO3

according ly limiting reagent is O2

from the balanced equation 3 moles of O2 is giving 2 moles of SO3

0.1562 moles of O2 will produce 2/3 (0.1562) = 0.1040 moles of SO3 will produce

weight of the SO3 theritically = 0.1041 mole x 80.06 g/mole

= 12.50 grams