Question

The average human body contains 5.60L of blood with a Fe2+ concentration of 3.20

The average human body contains 5.60L of blood with a Fe2+ concentration of 3.20

Homework Answers

Answer #1

  assuming that 1 CN- attaches to 1 Fe2+ and that "sequesters" the iron...

moles Fe attached to CN-.....
12.0 mL NaCN x (1 L / 1000 mL) x (23.0 mmole / L) x (1 mole / 1000 mMole) x (1 mole CN- / 1 mole NaCN) x (1 mole Fe2+ / 1 mole CN-) = 2.76x10^-4 moles Fe2+

total moles Fe2+ in your blood...
5.60 L x (3.20x10^-5 moles / L) = 1.792x10^-4 moles Fe2+

% Fe attached to CN- = 100%.. there is more CN- than Fe2+

*************
Now that I've read Joshua's answer, I guess it depends on how you intrepret this problem... if you mean this...

Fe2+ + 2 CN- ------> Fe(CN)2, then by all means...

moles Fe attached to CN- goes by this...
12.0 mL NaCN x (1 L / 1000 mL) x (23.0 mmole / L) x (1 mole / 1000 mMole) x (1 mole CN- / 1 mole NaCN) x (1 mole Fe2+ / 2 mole CN-) = 1.39x10^-4 moles Fe2+

and you end up with 1.39 / 1.792 x 100% = 77.57% bound Fe..

*********
however....

Fe2+ in blood is predominantly found in hemoglobin. The chemistry of hemoglobin binding with O2 and CN- is not a chemical reaction but rather a coordination complexation.

Each heme group contains 1 Fe2+ which can reversibly bind with 1 O2. It does NOT react with O2. Same goes for carbon monoxide and CN-. 1 CN- ion "binding" to that Fe2+, which it will because the Fe2+ / CN- complexation is preferred over Fe2+ / O2, will prevent the complexation of the heme Fe2+ with O2 thus "sequestering" the Fe2+

***********
so my advice to you is this..... submit either answer or both and explain your rationale then ask your instructor whether 1 CN- sequesters 1 Fe2+ or whether 2 CN- sequesters 1 Fe2+...

************

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The average human body contains 6.40 L of blood with a Fe2+ concentration of 1.40×10−5M ....
The average human body contains 6.40 L of blood with a Fe2+ concentration of 1.40×10−5M . If a person ingests 11.0 mL of 19.0 mMNaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically.
The average human body contains 5.60 L of blood with a Fe2+ concentration of 1.70×10−5 M...
The average human body contains 5.60 L of blood with a Fe2+ concentration of 1.70×10−5 M . If a person ingests 10.0 mL of 24.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 5.90 L of blood with a Fe2+ concentration of 3.10×10−5 M...
The average human body contains 5.90 L of blood with a Fe2+ concentration of 3.10×10−5 M . If a person ingests 7.00 mL of 18.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 5.40 L of blood with a Fe2+ concentration of 2.70×10−5 M...
The average human body contains 5.40 L of blood with a Fe2+ concentration of 2.70×10−5 M . If a person ingests 11.0 mL of 25.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 5.80 L of blood with a Fe2+ concentration of 2.00×10−5 M...
The average human body contains 5.80 L of blood with a Fe2+ concentration of 2.00×10−5 M . If a person ingests 12.0 mL of 15.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.30×10−5 M...
The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.30×10−5 M . If a person ingests 12.0 mL of 23.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 5.10 L of blood with a Fe2+ concentration of 2.60×10−5mol L−1....
The average human body contains 5.10 L of blood with a Fe2+ concentration of 2.60×10−5mol L−1. If a person ingests 7.00 mL of 23.0 mmol L−1mmol L−1 NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically.
The average human body contains 5.70 L of blood with a F e 2+ concentration of...
The average human body contains 5.70 L of blood with a F e 2+ concentration of 3.10×10−5 M . If a person ingests 6.00 mL of 11.0 mM NaCN , what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically.
Average human blood contains 300 nmoles of hemoglobin () per liter of plasma and 2.2 mmol...
Average human blood contains 300 nmoles of hemoglobin () per liter of plasma and 2.2 mmol per liter of whole blood. Calculate the molar concentration in each of these media. Molar concentration in plasma = M and nM Molar concentration in whole blood = M and mM pHb in plasma and human serum. pHb in plasma = pHb in human serum =
An average human infant’s blood serum contains 5-10 milliequivalents (mEq) of potassium per liter. Calculate this...
An average human infant’s blood serum contains 5-10 milliequivalents (mEq) of potassium per liter. Calculate this concentration range in both normality and ppm.