Question

consider the following reaction CH3CL+ 3CL2------ CCL4 +3HCL

a. express the relative rate of the reaction with respect to each reactant and product

b.if the rate of production of HCL is 0.060Ms-1 what is rate of reaction.

Answer 1

The reaction:

CH3Cl+ 3Cl2------ CCl4 +3HCl

reactants --> poducts

a) relative rates:

CH3Cl:

1:3 CH3Cl and Cl2

d[Cl2]/dt = 3/1 * d[CH3Cl]/dt

d[CCl4]/dt = -1/1 * d[CH3Cl]/dt

d[HCl]/dt = -3/1 * d[CH3Cl]/dt

Cl2 respect to to all others

d[CCl4]/dt = -1/3 * d[Cl2]/dt

d[HCl]/dt = -1/1 * d[Cl2]/dt

CCl4 respect to to all others

d[HCl]/dt = + 3/1 * d[CCl4]/dt

b.if the rate of production of HCL is 0.060Ms-1 what is rate of reaction.

Rate of reaction:

Overall rate must be based on 1 mol of species so

Rate of reaction --> 1/3*d[HCl]/dt

Rate of reaction --> 1/3*0.06 M/s

Rate of reaction = 0.02 M/s