Question

An experiment calls for 50mL of a 0.5 M Aqueous solution of sodium hydrogen carbonate, describe how you would make up such a solution

Answer 1

The molecular formula of Sodium hydrogen carbonate is

The molecular weight of is .

We know the molarity can be defined as the number of moles of solute present in one liter of solution.

The mathematical expression is written as

w= required mass of solute

v= volume

MW= molecular weight.

Here in the question, it is asking to prepare 50 mL of 0.5 M solution for that means we need to know the mass of the solute.

Now we have

w = ?

MW = 84.007 g/mol

v = 50 mL

Now apply the molarity formula

Hence 2.1 g of Sodium hydrogen carbonate is required to prepare 0.5M of solution of sodium hydrogen carbonate aqueous solution in 50 mL.