Question

Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration of that chemical was changed and other chemicals are held constant.

the H2O2 concentration is doubled:

the KCl concentration is doubled:

the catalyst concentration is doubled:

Possible Answers:

Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration of that chemical was changed and other chemicals are held constant.

the H2O2 concentration is doubled

      [ Choose ]            the rate of oxygen collected is approximately half as fast            there is little or no effect on the rate of oxygen collection            the rate of oxygen collected is approximately twice as fast            the rate of oxygen collected is approximately four times slower            the rate of oxygen collected is approximately four times faster      

the KCl concentration is doubled:

the rate of oxygen collected is approximately half as fast            there is little or no effect on the rate of oxygen collection            the rate of oxygen collected is approximately twice as fast            the rate of oxygen collected is approximately four times slower            the rate of oxygen collected is approximately four times faster

the catalyst concentration is doubled

Answer 1

Hi you have copied text only, but it is not exactly representing what are you looking for, so i have searched for it and found below question, if anything else to be clarified, please comment below at comments secion, so that i will try to respond asap.

When the amount of H₂O₂ is doubled while KI is kept constant, the rate of reaction doubles.

When the amount of KI is doubled and the amount of H₂O₂ is halved, the rate stays nearly constant.

2H₂O₂ (aq) → O₂(g) + 2H₂O (l) ------------- first order kinetics reaction.

Catalysts are KI, FeCl3 only, KCl is not a catalyst. Order: KI < MnO2 < Pb < FeCl3.

H₂O₂ + I^– -> IO^– + H₂O (Step 1)

H₂O₂ + IO^– -> I^– + H₂O + O₂ (Step 2)

It can be seen that the iodine ion (provided by the KI solution) is a product as well as a reactant.

Hope this helped you!

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