For each strong acid solutions, determine [H3O+],[OH−], and pH. (So, there should be three answers for each question).
1. 0.22 M HCl
2. 1.8×10−2 M HNO3
3. a solution that is 6.1×10−2 M in HBr and 1.9×10−2 M in HNO3
4. a solution that is 0.755% HNO3 by mass (Assume a density of 1.01 g/mL for the solution.)
1) As HCl is a strong acid - there are , [H3O+] = 0.22 M, [OH-] = Kw/ [H3O+] = (1.0*10-14/0.22) = 4.54e-14 M,
pH = -log [H3O+] = - log(0.22) = 0.65
2)
As HNO is a strong acid - there are , [H3O+] = 1.8*10-2 M, [OH-] = Kw/ [H3O+] = (1.0*10-14/1.8*10-22 M) = 5.55e-13 M,
pH = -log [H3O+] = - log(1.8*10-2 M) = 1.77
3) Total [H3O+] = 6.1*10-2 + 1.9*10-2 = 8*10-2 M, [OH-] = 1.25*10-13 M. pH = - log [H3O+] = -log (8*10-2 )
= 1.09
4) Number of mols of HNO3 = 0.755 g / 63 g/mol = 0.0119 mol
Thus - Molarity = 0.0119 mol / 0.1 L = 0.119 M
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