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calculate the ph of a 0.15 M solution of FeSO4... I know that you use the...

calculate the ph of a 0.15 M solution of FeSO4...

I know that you use the Kw=Ka*Kb relationship but how do you know the Ka=10^3? and that you are suppose to solve for Kb? what kind of solution is this and how do you know?

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Answer #1

PH = 14-POH

    = 14-6.456

   = 7.544 >>>> answer

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