For PbCl3−, Kform = 2.5 × 101. Use this information plus the Ksp for PbCl2 to calculate Kc for the following reaction: PbCl2(s) + Cl-(aq) <---> PbCl3-(aq)
The Kform PbCl3- = 2.5 × 101
Pb+2 + 3Cl- --> PbCl3-
Kform = [PbCl3-] / [Pb+2][Cl-]^3 ..........(1)
Pb+2 + 2Cl- = PbCl2
Ksp = [Pb+2] [Cl-]^2 .....(2)
We have to calculate
PbCl2(s) + Cl-(aq) <---> PbCl3-(aq)
Kc = [PbCl3-] / [Cl-] ..........(3)
So we have to equate expression (3) with expression 1 and 2.
Let us multiply the two
Kform X Ksp = [PbCl3-] / [Pb+2][Cl-]^3 X [Pb+2] [Cl-]^2 = [PbCl3-] / [Cl-] = Kc
Ksp = 1.6 x 10^-5
Kc = 2.5 × 101 X 1.6 x 10^-5 = 4 X 10^-4
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