Question

27.26 mL 0.040 M Na₂[H₂edta] solution is required to reach the end point when added to a 20.00 mL aliquot of a zinc sulfate solution.  How many moles of Zn²⁺are present in 200.00 mL of the zinc sulfate solution?

Answer 1

Since 1 mol Zn⁺² reacts with 1 mol EDTA to form the complex,

The number of mols of Zn⁺² present in 200 mL ZnSO₄ = ((27.26 mL)(0.040 mol/L) / 20 mL)200 mL = 10.984 mmol

                                                               = 0.010984 mol