Give the possibilties in stucture for a compound with the formula C6H10
Given the molecular fomula,
First step is to calculate the Degree of Unsaturation (U), because it gives you an idea about the number of double bonds or rings in the structures. It is calculated as:
where C is number of Carbons,
H is number of Hydrogens,
N is number of Nitrogens,
X is number of Halogens,
In the given molecular formula, there are no halogens and nitrogens. And, number of C = 6, number of H =10
Therefore,
The possibilities with U = 2 are:
a) 2 rings,
b) 1 ring and 1 double bond
c) 2 double bonds
d) 1 triple bond
The structures are as follows,
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