The rate constants for the reaction of oxygen atoms with benzene have been reported to be:
k (M-1 s-1) 1.44 x 107 3.03 x 107 6.90 x 107
T (oC) 27.2 68.0 119
Determine the activation energy and pre-exponential constant for this reaciton
Solution:
We know Arhenium equation,
K = Ae(-E/RT)
ln K = ln A - E/RT
Plot a graph of lnK vs 1/T, the slpope of the straight line is -E/R and Intercept is ln A
so,
K | lnK | T C | T K | 1/T |
1.44 * 107 | 16.48 | 27.2 | 300.2 | 0.00333 |
3.3 * 107 | 17.31 | 68 | 341 | 0.00293 |
6.9 * 107 | 18.05 | 119 | 392 | 0.00255 |
The graph is as follows:
Slope of the line = Y/X
= -1.57/0.0078
= -2012.82
Activation energy is = -Slope * R
= - (-2012.82) * 8.314
Ea = 16734 J
Y intercept of the line 16.05
ln A = 16.05
A = 43.62
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