Question

In a titration experiment, 36.9 mL of 0.989 M HCOOH neutralizes 35.5 mL of Ba(OH)2. What is the concentration of the Ba(OH)2 solution?

Answer 1

Let M1, V1 and M2, V2 be the molarity (concentartion) , volume of HCOOH (formic acid) and Ba(OH)2 (Barium hydroxide) respectivelly,

For, HCOOH, M1 = 0.989 M, V1 = 36.9 mL

and for Ba(OH)2, M2 = ? and V2 = 35.5 mL

On neutralization i.e. at the point of equivalence Number of milimoles of acid are equal to the number of milimoles of base.

Number of milimoles = Molarity x Volume

So, Number of milimoles of HCCOH = Number of milimoles of Ba(OH)2

M1V1 = M2V2

0.989 x 36.9 = M2 x 35.5

36.49 = M2 x 35.5

M2 = 36.49 /35.5

M2 = 1.03 M

Concentration of Ba(OH)2 will be 1.03 M