Sodium reacts with oxygen to produce sodium oxide. 4Na(s)+O2(g)→2Na2O(s).How many grams of O2 are needed in a reaction that produces 75.8 g of Na2O?
We have the reaction that
In this reaction
1 mole of Oxygen can produce 2 mole of
We know that 1 mole of the molecule is equal to molecular mass of the molecule.
1 mole of oxygen = 32 gm of oxygen
1 mole of is 62 gm of
and 2 mole of is 124 gm of
We can write that
32 gm of oxygen gas produce 124 gm of
It can be written in other way that
124 gm of is produced from 32 gm
Then 75.8 gm of will produced from
Hence for the production of 75.8 g of , we need 19.55g of .
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