Question

Given: HCl (aq) + H2O <> H3O^+ + Cl^- consider the following changes: a) add HCl   ...

Given: HCl (aq) + H2O <> H3O^+ + Cl^-

consider the following changes: a) add HCl    b) add NaOH   c) add H2   d) Heat

Determine the consequence of each. Please show all relevant work/steps for study purposes. Thanks in advance!

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Answer #1

Keq = [H3O+] [Cl-]/ [HCl]

a)When more HCl is added, Keq decreases and to compensate for this more of [H3O+] [Cl-] are formed.

b) when NaOH is added, some of the HCl gets consumed depending upon the concentrations. Hence [HCl] decreases and to keep the equilibrium constant [H3O+] and [Cl-] decrease.

c) addtion of hydrogen does not have any effect

d) when heated the value of Kc is already large and complete dissociation of HCl ( being strong acid) takes place and hence K does not get effected.

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