Data given: Depression in freezing point = Difference between the freezing point of water and that of salt solution = 6.7 degree celsius
And cryoscopic constant for water = 1.86
The depression in freezing point is related to molality of the solution by the equation
depression in freezing point = Kf molality therefore, 6.7 = 1.86 x molality
Molality = 6.7/1.86 = 3.60 mol kg-1 of the solvent
This means in the 1 kg of water contains 3.6 mol of salt = 3.6 x58.8 g of salt(58.5 g mol-1 is the molar mass of salt)
Thus 1 kg of water contains 210.7 g of salt
The percent of salt in the solution is therefore, 210.7x100/1000= 21.07%
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