Calculate Ea for the uncatalyzed reactions. Use equation 9 and two uncatalyzed reactions that are identical in every aspect except for temperature.
Eq. 9: ln k2/k1 = (Ea/R)(1/T1 - 1/T2)
Reaction | [H2O2]M | [I-]M | Δ[I2] | Reaction Time, Δt (s) | Reaction Temp. (K) | RATE = Δ[I2]/Δt (M/s) | Apparent rate, constant, k' | ln k' | 1/T |
1 | 0.008 | 0.015 | 1.25E-04 | 126 | 295.15 | 9.92E-07 | 8.27E-03 | -4.79546 | 0.003388 |
2 | 0.012 | 0.015 | 1.25E-04 | 136 | 295.15 | 9.19E-07 | 5.11E-03 | -5.2773 | 0.003388 |
The temperatures are the same ( T1 and T2 ) therefore Ea for the uncatalyzed reactions can not be calculated.
If there was an error writing data Please leave a comment and I'll help you gladly.
With the temperature of 293.15K you commented:
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