Question

] solutions are 0.60%, and 0.30% NaOCl by mass. Calculate the molarity of OCl in each of these solutions. assumption that every 100g of solution is 100mL.difference in calculation of molarity before dilution with the dye and molarity after dilution with the dye

mix the bleach and the dye solutions, the concentration (molarity) of the bleach is cut in half. [OCl-

Answer 1

Given that that every 100g of solution is 100mL

Calulate the mass of NaOCl-

100 g * 0.60%, = 0.6 g

Molar mass of NaOCl = 74.44 g/ mol

Calculate the moles of NaOCl-
0.6 g / 74.44 g/mole = 8.06*10^-3 moles

100 mL = 0.100L
Molarity = Number of moles / volume in L

=8.06*10^-3 moles/0.100liter

=0.081 M

100 g * 0.30%, = 0.3 g

Molar mass of NaOCl = 74.44 g/ mol

Calculate the moles of NaOCl-
0.3 g / 74.44 g/mole = 4.03*10^-3 moles

100 mL = 0.100L
Molarity = Number of moles / volume in L

=4.03*10^-3 moles/0.100liter

=0.040 M