Draw the Born-Haber cycle for the formation of CaH2, and calculate the value for lattice energy? (You will have to look up the required thermodynamic data)
Heat of formation= Heat of atomization+ Dissociation energy+ (sum of Ionization energies)+ (sum of Electron
affinities)+ Lattice energy
Heat of formation of CaH2 = -181.5 Kj/mol
Heat of atomization --> Ca(s) --> Ca(g) = 187 Kj/mol
IE1 + IE2 of Ca ---> 589.8 and 1145.4 KJ/mol
Dissociation energy of H2 ----> 436 Kj/mol
Electron affinity = 72.769 KJ/mol *2 = 145.538 KJ/mol
Substitute in the above formula
-181.5 = 187 + 589.8 + 1145.4 + 436 + 145.538 + Lattice energy
Lattice energy = -2685.238 KJ/mol
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