Find the ionic strength of a 4 mM of CaCl2. What are the activities of Ca2+ and Cl-.
Since CaCl2 produces one Ca2+ ion and two Cl- ion, hence the molarities of the ions in this case would be as follows:
[CaCl2] = 4 mM =0.004 M
m+ = 0.004 , m- = 2 x 0.004 = 0.008;
z+ = 2; z- = 1
Hence, Ionic strength, I = 1/2( 0.004 x 22 + 0.008 x 12) = 0.012.
The mean activity coefficient is given by
"A" value, temperature and solvent not mentioned in question.
For water at 25 oC, A = 0.509
-0.509 X 2 x 1 x (0.012) 1/2
= -0.111
So, 0.774
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