A 25.00 mL sample of a solution required 21.40 mL of 0.1185 M NaOH to reach the visual endpoint. How many moles of H+ were present in the aliquot? Give your answer to four decimal places.
no of moles of NaOH = molarity of NaOH * volume in L
= 0.00253 mole
no ofmoles of NaOH = no of moles of Acid
assume stock solution is 100ml
since titrate 25ml out of 100ml no of H+ ions is 4 time = 4*0.00253 = 0.01012 moles of H+
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