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A 25.00 mL sample of a solution required 21.40 mL of 0.1185 M NaOH to reach...

A 25.00 mL sample of a solution required 21.40 mL of 0.1185 M NaOH to reach the visual endpoint. How many moles of H+ were present in the aliquot?  Give your answer to four decimal places.

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Answer #1

no of moles of NaOH = molarity of NaOH * volume in L

                               = 0.1185*0.0214

                              = 0.00253 mole

no ofmoles of NaOH = no of moles of Acid

assume stock solution is 100ml

since titrate 25ml out of 100ml no of H+ ions is 4 time = 4*0.00253 = 0.01012 moles of H+

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