Find the [OH-] and pH of a 0.66 M methylamine solution
Find the [OH-] and pH of a 0.66 M methylamine solution
Methylamine solution concentration is 0.66 M and methylamine
base constant (kb) = 4.4x10-4.
CH3NH2 + H2O ->
[OH-] + [CH3NH3+]
0.66 M____0______0________0______(before reaction; x: production
concentration)
___x_____________ x________x______(reacting with H2O is
not considered a reactant)
(0.66- x)___________-x_______-x______(after reaction)
Note: we don't count H2O on calculation.
Formula of Kb =
[CH3NH3+][OH-]/[CH3NH2]
-> 4.4*10-4 = x2/(0.66-x)
(2.904*10-4) – (4.4 *10-4) x = x2
x2 + (4.4 *10-4) x - (2.904*10-4) = 0
If we solve this quadratic equation we will get x = -0.0172 or x= 0.0168
Negative value is not possible so x= 0.0168
[OH-] = 0.0168 M
pOH = -log [OH-] = -log (0.0168) = 1.77
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