How many milliliters of 5.5 M HCl solution are needed to obtain 0.14 mol of HCl?
Express the volume in milliliters to two significant digits
How many moles of KBr are present in 140. mL of a 0.128 M solution?
Express the amount in moles to three significant digits.
Molarity = (no. of moles)/volume of solution(in L)
volume of 5.5 M HCl solution needed to obtain 0.14 mol of HCl is:
5.5 M = 0.14 mol/volume
or, volume of solution = 0.14/5.5 = 0.025 L = 25. mL
Hence, 25. mL of 5.5 M HCl solution is needed to obtain 0.14 mol of HCl.
The number of moles of KBr present in 140. mL of a 0.128 M solution is given by:
0.128 M = (number of moles)/(140 x 10-3 L)
number of moles = (0.128)x(0.140) = 0.0179 mol
Hence, 0.0179 mol of KBr are present in 140. mL of a 0.128 M solution
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