Part A For the reaction 2CH4(g)⇌C2H2(g)+3H2(g) K = 0.140 at 1595 ∘C . What is Kp for the reaction at this temperature? Part B For the reaction N2(g)+3H2(g)⇌2NH3(g)
2CH4(g)⇌C2H2(g)+3H2(g) K = 0.140
KP = KC(RT)n
n = no of moles of products- no of moles of reactants in gases state
= [1+3] -[2]
= 2
R = 0.0821L-atm/mole_k
T = 1595C0 = 1595+273 = 1868K
KP = 0.14(0.0821*1868)2
= 0.14*23520.14 = 3292.82 >>>> answer
Part- B
N2(g)+3H2(g)⇌2NH3(g)
KP = KC(RT)n
n = no of moles of products- no of moles of reactants in gases state
= 2-4 = -2
KP = 0.14(0.0821*1868)-2
= 0.14/23520.14
= 5.95*10-6
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