Question

Part IV. Based on the average number of moles of IO3- in your samples, and the...

Part IV. Based on the average number of moles of IO3- in your samples, and the initial volume of those samples, what is the solubility of Ca(IO3)2 in mol/L of the saturated solution in pure water? You should report 3 significant figures, e.g. 0.00603.

Avg. Moles :0.000108 moles

Initial Vol: 6.52 mL

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Homework Answers

Answer #1

In 1 mole of Ca(IO3)2 , there are 2 moles of IO3-

or

2 moles of IO3- present in 1 mole of Ca(IO3)2.

1 moles of IO3- present in 1/2 mole of Ca(IO3)2.

0.000108 moles of IO3- present in 0.000108/2 mole of Ca(IO3)2.

0.000108 moles of IO3- present in 0.000054 mole of Ca(IO3)2.

Now,

In 6.52 mL, 0.000054 mole of Ca(IO3)2 present.

In 1 mL, (0.000054/6.52) mole of Ca(IO3)2 present.

In 1000 mL, {(0.000054/6.52) (1000)} mole of Ca(IO3)2 present.

In 1000 mL, 0.00828 mole of Ca(IO3)2 present.

In 1 L, 0.00828 mole of Ca(IO3)2 present.

So, 0.00828 mole per liter of Ca(IO3)2.

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