Question

How many mL of aqueous 0.100 M HCl must be used to react completely with 25.0 g of KOH (s)? The molar mass of HCl is 36.46 g; the molar mass of KOH is 56.12 g.

Answer 1

first write the balanced equation

KOH + HCl -------> KCl + H2Ofrom this balanced equation it is clear that one mole of HCl required one mole of HCl

no of moles of KOH = weight of KOH / molar mass of KOH

= 25 g / 56.12 g/mol

= 0.4454 moles

but from equation it is clear that one mole of KOH required one mole of HCl

so no of moles of HCl = 0.4454

now we know the molarity of HCl and moles of HCl we can calculate the volume of HCL using molarity formula

M = no of moles /volume in liters

0.1 = 0.4454 / volume in liters

volume in liters = 0.4454 / 0.1

= 4.451 L or

=4454 mL