Question

a. How many equivalents of NaOH are needed to titrate an inorganic phosphate solution (H3PO4 <-->...

a. How many equivalents of NaOH are needed to titrate an inorganic phosphate solution (H3PO4 <--> H2PO4^- <--> HPO4^2- <-->PO4^3-) from pH2.15 to pH9.60? (assume pk1=2.15; pk2 6.82; pk3=12.38)

b. If in "a" above you would have 100 mL of 50.0mM inorganic phosphate solution at pH 2.15, how many mL of 0.500M NaOH would you have to add to get to pH 9.6?

c. Suppose, by accident, you added 1.00 mL extra 0.500M NaOH than you needed in "b" above. What would be the pH of the final solution?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
What is the pH of a phosphate solution made by the addition of 6 equivalents of...
What is the pH of a phosphate solution made by the addition of 6 equivalents of NaOH to an initial solution of phosphoric acid? The pKa values are pK1 = 12, pK2 = 20, pK3 = 40 a.)7.4 b.)10.6 c.)12.6 d.)8.8
A liter of pH 7.20 phosphate buffer is needed for a certain experiment. The Henderson-Hasselbach equation...
A liter of pH 7.20 phosphate buffer is needed for a certain experiment. The Henderson-Hasselbach equation will be sufficiently accurate for your determination of pH. The pK’s for possibly relevant phosphate species are: H3PO4 ↔ H2PO4- + H+ pK = 2.15 H2PO4- ↔ HPO4-2 + H+ pK = 7.20 HPO4-2 ↔ PO4-3 + H+ pK = 12.4 0.100 Moles of H3PO4 were dissolved in about 800 mL of water, and the pH was adjusted to 7.20 using a standardized pH...
How many mL of a 0.100 M NaOH solution would be needed to titrate 0.156 g...
How many mL of a 0.100 M NaOH solution would be needed to titrate 0.156 g of butanoic acid to a neutral pH endpoint?
How many grams of potassium dihydrogen phosphate (MW=136.09 g/mol) and dipotassium hydrogen phosphate (MW=174.18 g/mol) would...
How many grams of potassium dihydrogen phosphate (MW=136.09 g/mol) and dipotassium hydrogen phosphate (MW=174.18 g/mol) would be needed to produce a 2 L buffer solution of pH 6.8 at 100 mM solute concentration? The pKa’s for phosphoric acid, a triprotic acid, are 2.15, 6.82 and 12.38.
Consider 2.50 L of a buffer solution made from NaOH and 3.50 M H3PO4 at pH...
Consider 2.50 L of a buffer solution made from NaOH and 3.50 M H3PO4 at pH 2.23 that has a total concentration of phosphate containing species of 0.188 M. How many mL of 2.00 M HCl must be added to the buffer solution to change its pH by 1.25 units?
A certain volume of 1M NaOH is needed to titrate 500mL of a 0.2M solution of...
A certain volume of 1M NaOH is needed to titrate 500mL of a 0.2M solution of a weak acid(pKa=4.0) to the equivalence point. You then titrate a 0.4M solution of this same weak acid but to pH=4.0. If you used the same amount of 1.0 M NaOH for the second titration as for the first, the volume of 0.4M solution titrated is A)100mL B) 250mL C)500mL D)1000mL E)200mL Explain and show all work.
1. Show the calculations required for preparing the buffers in this exercise. The pKa values for...
1. Show the calculations required for preparing the buffers in this exercise. The pKa values for H3PO4 are 2.15, 6.82, 12.32. Note that you’ll be using the pKa value of 6.82. Why? Method 1 a. Calculate the grams of NaH2PO4*H2O needed to prepare 100.0 mL of a 100mM solution. b. Calculate the amount of 1.00M NaOH you expect to add to adjust the pH of your NaH2PO4 solution to 7.0. Method 2 c. Using the Henderson-Hasselbalch equation, calculate the g...
How many liters of 0.250 M of NaOH are needed to create 750.0 mL of a...
How many liters of 0.250 M of NaOH are needed to create 750.0 mL of a 100.00 mM histidine buffer at pH=2.50? If you added 1.00 mL of a 6.00 M HCl to the buffer (750.0 mL) in the part above, what would be the resulting pH? If you added 1.00 mL of a 6.00 M HCl to 750 mL of pure water what would be the pH of this solution be? CIRCLE BOTH ANSWERS
A 0.860 M solution of NaOH is used to titrate the following solutions to the equivalence...
A 0.860 M solution of NaOH is used to titrate the following solutions to the equivalence point. How many milliliters of NaOH do you need when titrating against a concentration for Acetic Acid is 0.900 M. After determining the mL of NaOH, calculate the pH for both a. and b. a. 50.0 mL of 0.0750 M HCl b. 40.0 mL of CH3COOH How many millilters of NaOH do you need when titrating aginst
how many milliliters of 0.15 M HCl are needed to titrate to the end point 100.0...
how many milliliters of 0.15 M HCl are needed to titrate to the end point 100.0 mL of a solution that contains 2.35g of NaOH per liter?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT