Question

how to compute what orbital coefficients one would need to generate the types of orbitals that are found in H2S with the bond angle 92 degrees?

Answer 1

Sulfur with 3s2 3p4 valence shell electronic configuration has two unpaired electrons in the 3p orbital. These may combine with the two electrons of the approching atom to give two bonds. Along with that it also has two lone pairs of electrons of 3s and 3p orbital. In H2S, the hydrogen atom gives its one electron and pairs with the 3p orbital electrons to form two HS bonds. The lone pair stays on top far from each other giving the geometry similar to tetrahedral as would be the case in H2O molecule. the non-bonding orbitals push the SH bonds closer enough to reduce the usual tetrahedral angle of 109 to 92 degrees.