The standard Gibbs free energy change for hydrolysis or pure ATP to pure ADP is -31KJ/mol. The reaction is written ATP = ADP +Pi. What is the Gibbs energy of reaction in an environment at 37 C in which the ATP, ADP, and Pi concentrations are all 1mmol/L or 1 µmol/L?
Go = -31 kJ /mol
Q = [ADP][Pi]/[ATP]
Q = 1 x 10^-6 (1 x 10^-6) / 1x 10^-6
Q = 1.0 x 10^-6
T = 37 + 273 = 310 K
G = Go + RT lnQ
= -31 + 8.314 x 10^-3 x 310 x ln (1.0 x 10^-6 )
= -66.60 kJ/mol
Gibbs energy of reaction = - 66.60 kJ/mol
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