Question

a 500 ml sample of water was heated from 10 k to 50 k. how
much heat was gained?

Answer #1

To calculate the heat gained by water , we'll use: q = mcT

where, m = mass of substance in grams

c = specific heat of the substance (in
Jg^{-1}K^{-1})

T = Temperature change

step 1 : to calculate the temperature change:

Intial temperature , T1 = 10K , Final Temperature, T2 = 50K

T = T2 - T1 = 50K - 10K = 40K

Step 2 : to calculate mass of water

Density of water = 1g/mL , Volume of water = 500 mL

mass of water, m = Density of water X volume of water = 1g/mL X 500mL

mass of water, m = 500g

we know that the specific heat of water , c = 4.184
Jg^{-1}K^{-1}

step 3 ; To calculate heat gained :

q = mcT = (500g)(4.184
Jg^{-1}K^{-1})(40K) = 83680 J

**Heat gained, q = 83.68 kJ**

A 186.6 g sample of water at 12.5°C is heated to steam at
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kcal

A 186.6 g sample of water at 12.5°C is heated to steam at
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kcal

An aluminum electric tea kettle with a mass of 500 g is heated
with a 500-W heating coil. How long will it take to heat up 1.0 kg
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Stocks
3 M NaCl
10% (w/v) sodium dodecyl sulfate
20 mg/ml Proteinase K
You need your extraction buffer to contain:
Final
30 mM NaCl
0.2% (w/v) sodium dodecyl sulfate
1.5 mg/ml Proteinase K
How much of each is needed to make
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Component:
____________
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____________
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Cwater= 4.186 J/g
C Csteam= 2.02 J/g
C Vaporization:
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A)
Calculate how much energy is required to heat 20.0 mL of water from
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