Question

The specific heat of water is 4.18 J/(g⋅∘C). Calculate the molar heat capacity of water.

Answer 1

Answer – We are given, specific heat of water = 4.18 J/g?^?C

We know the specific heat of water is for 1 g is 4.184 J, means for raising the temp by 1^oC for 1 g of water we need 4.184 J.

The molar heat capacity is for the per mole of water

So, moles of water = 1 g / 18.015 g.mol^-1

                               = 0.0555 moles

So, molar heat capacity = 4.184 J /0.0555 moles

                                       = 75.4 J/mol. ^?C