Which of the following reactions could proceed as written?
Cl2(aq) + 2 NaBr(aq) >> 2 NaCl(aq) + Br2 (aq)
l2(aq) + 2 NaBr(aq) >> 2 Nal(aq) + CI2 (aq)
Cl2(aq) + 2 NaI(aq) >> 2 NaCl(aq) + I2 (aq)
Cl2(g) + 2 e− is in equilibrium with 2 Cl− +1.36
Br2(aq) + 2 e− is in equilibrium with 2 Br− +1.0873
I2(s) + 2 e− is in equilibrium with 2 I− +0.54
Therefore,
the most positive tend to REDUCE, then
Cl2 > Br2 > I2>
Cl2(aq) + 2 NaBr(aq) >> 2 NaCl(aq) + Br2 (aq) --> will not happen, since Cl2 will remain as Cl2
l2(aq) + 2 NaBr(aq) >> 2 Nal(aq) + CI2 (aq) --> will happen, since Cl- ions tends to form Cl2
Cl2(aq) + 2 NaI(aq) >> 2 NaCl(aq) + I2 (aq) --> will not happen, since Cl2 will remain as Cl2
Get Answers For Free
Most questions answered within 1 hours.