At 8:00 A.M., a patient receives a 1.1-μg dose of I-131 to treat thyroid cancer.
Part A:
If the nuclide has a half-life of 8.0 days, what mass of the nuclide remains in the patient at 4:00 P.M. the next day? (Assume no excretion of the nuclide from the body.)
Express your answer using two significant figures.
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m = | μg |
Given:
Half life = 8 days
use relation between rate constant and half life of 1st order reaction
k = (ln 2) / k
= 0.693/(half life)
= 0.693/(8)
= 8.662*10^-2 days-1
we have:
[A]o = 1.1 ug
t = 24 hours + 8 hours
= 1 day + 1/3 days
= 1.33 days
k = 8.662*10^-2 days-1
use integrated rate law for 1st order reaction
ln[A] = ln[A]o - k*t
ln[A] = ln(1.1) - 8.662*10^-2*1.33
ln[A] = 9.531*10^-2 - 8.662*10^-2*1.33
ln[A] = -1.99*10^-2
[A] = e^(-1.99*10^-2)
[A] = 0.980 ug
Answer: 0.980 ug
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