Use the thermodynamic data provided below to determine ΔG (in
kJ/mol) for the condensation of C2H5OH at
64.02 °C if the initial partial pressure of
C2H5OH is 1.99 atm. Report your answer to one
decimal place in standard notation (i.e. 123.4 kJ/mol).
Substance | ΔH°f (kJ/mol) | S° (J mol-1K-1) | ||
C2H5OH (l) | -277.7 | 160.7 | ||
C2H5OH (g) | -235.1 | 282.7 |
For C2H5OH (l)
G = H - TS
G = -277.7 kJ/mol - 337.02 (0.1607kJ mol-1K-1)
G = -331.85 kJ mol-1
For C2H5OH (g)
G = H - TS
G = -235.1 kJ mol-1- 337.02 (0.2827kJ mol-1K-1)
G = -330.375 kJ mol-1
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